0=0.01x^2-x+19

Solution for 0=0.01x^2-x+19 equation:

0=0.01x^2-x+19

We move all terms to the left:

0-(0.01x^2-x+19)=0

We add all the numbers together, and all the variables

-(0.01x^2-x+19)=0

We get rid of parentheses

-0.01x^2+x-19=0

a = -0.01; b = 1; c = -19;
Δ = b2-4ac
Δ = 12-4·(-0.01)·(-19)
Δ = 0.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{0.24}}{2*-0.01}=\frac{-1-\sqrt{0.24}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{0.24}}{2*-0.01}=\frac{-1+\sqrt{0.24}}{-0.02}
$